Maurizio Bevilacqua
ITA · FIDE ID 803332 · 6 tournament games since 2022
Standard
2021
#615 in ITA (active)
Rapid
2026
#500 in ITA (active)
Blitz
2067
#301 in ITA (active)
Score
33%
2 W · 0 D · 4 L
Opp. avg
1951
Last 6 games
Last game
2024-10-06
1º Torneo Grand Prix Umbria Città di Spoleto
Prep summary
- As White: 1.d4 in 50% of games (scores 50%), otherwise 1.c4 (50%).
Based on 6 over-the-board games. 4 with White (25%), 2 with Black (50%).
Openings as White
First move
| 1.d4 | 2 | 50% |
| 1.c4 | 2 | 0% |
Most played
| Opening | Games | Score |
|---|---|---|
| Catalan Opening: Open Defense | 1 | 0% |
| English Opening: Symmetrical Variation, Ultra-Symmetrical Variation | 1 | 0% |
| Queen's Pawn Game: Colle System | 1 | 100% |
| Réti Opening: Anglo-Slav Variation, London Defensive System | 1 | 0% |
Openings as Black
Against 1.e4 (1 game)
| 1...c5 Sicilian Defense | 1 | 100% |
Against 1.d4 (1 game)
| 1...Nf6 Indian Defense | 1 | 0% |
Most played
| Opening | Games | Score |
|---|---|---|
| Sicilian Defense: Smith-Morra Gambit Accepted, Paulsen Formation | 1 | 100% |
| Nimzo-Indian Defense: Classical Variation, Noa Variation | 1 | 0% |
Recent games
| Date | Opponent and event | Result |
|---|---|---|
| 2024-10-06 | William Pecci (2045) 1º Torneo Grand Prix Umbria Città di Spoleto | L |
| 2024-10-06 | Daler Amonov (1909) 1º Torneo Grand Prix Umbria Città di Spoleto | W |
| 2024-10-05 | Alexandro Beliman (2110) 1º Torneo Grand Prix Umbria Città di Spoleto | L |
| 2024-10-05 | Giulio Cong Yan Saporito (1739) 1º Torneo Grand Prix Umbria Città di Spoleto | W |
| 2022-10-22 | Simon Ritzka 5th Kaltern Trophy 2022 | L |
| 2022-10-22 | Leonardo Loiacono 5th Kaltern Trophy 2022 | L |
Data: FIDE rating list (October 2026 list; national ranks count active players) and tournament games broadcast on Lichess since 2020 (open data, CC0). Results are matched to FIDE players by name or FIDE ID and may be incomplete. This page shows public chess results only. Is this you and you want the page removed? Email chessmoose1@gmail.com and we remove it.